A hoop (I=MR^2) is rolling along the ground at 7.0m/s. It comes to a hill and starts going up. Assuming no losses to friction, how high does it go

A hoop (I=MR^2) is rolling along the ground at 7.0m/s. It comes to a hill and starts going up. Assuming no losses to friction, how high does it go before it stops?

Answer: 5.0 m. 

Please tell me how to get h from 

Mgh = 1/2Mv^2 + 1/2Iw^2. 

show all steps to the equation.