I’m studying for my Chemistry class and don’t understand how to answer this. Can you help me study?
1. Deduce the identity of compound A and B, whose IR spectrum shows the following fingerprint and diagnostic signals.
Compound A
- 3500-2600 (broad) cm-1
- 1710 (intense) cm-1
- 1200 ( medium) cm-1
Compound B
- 3400-3200 (broad) cm-1
- 3100-2900 (broad) cm-1
- 1200 ( medium) cm-1
A.
Compound B is an alcohol
Compound A is a carboxylic acid
B.
Compound B is an alcohol
Compound A is an aldehyde
C.
Compound B is an aldehyde
Compound A is an carboxylic acid
D.
Compound A is an aldehyde
Compound B is an carboxylic acid
E.
Compound A is an alcohol
Compound B is a carboxylic acid
2. Deduce the identity of compound A and B, whose IR spectrum shows the following important fingerprint and diagnostic signals.
Compound A
- 3100-3080 ( medium, sharp) cm-1
- 3000-2850 (strong, intense) cm-1
- 1610 (medium, sharp) cm-1
Compound B
- 3300-3250 ( strong, sharp) cm-1
- 3000-2850 (strong, intense) cm-1
- 2100 (medium, sharp) cm-1
A.
Compound A is an Alkene ( sp2 C-H present)
Compound B is an Alkyne ( sp C-H present)
B.
Compound B is an Alkene ( sp2 C-H present)
Compound A is an Alkyne ( sp C-H present)
C.
Compound A is an Alkene ( sp2 C-H absent)
compound B is an Alkene ( sp2 C-H present)
D.
Compound B is an Alkene ( sp2 C-H absent)
compound A is an Alkene ( sp2 C-H present)
E.
Compound A is an Alkane
compound B is an Alkene
3. Which compounds would be consistent with the IR and NMR spectrum given below. (REFER TO LAB 2 PDF ATTACHED).
- Draw the structure of the compound
- Match all the peaks/ signals on the IR ; H-NMR and C-NMR spectra with the functional groups/ protons/ carbons present in the predicted molecule.
Chemical Formula: C6H12O; Molecular Weight: 100.16
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