The Chemistry
Years ago, an important precursor to acrylic acid (CH2=CHC=OOH), a key organic
building block for many useful products, was ketene (CH2=C=O). One way to
make ketene was the vapor-phase pyrolysis of acetone (CH3C=OCH3). Pyrolysis
means heating in the absence of oxygen. The overall endothermic reaction is:
CH3COCH3 CH2CO + CH4
Jeffreys (1964) claimed the rate is 1st order in acetone vapor. The following
elementary gas phase mechanism can explain this dependence and the products:
CH3COCH3 ⇔ CH3C.
O + .
CH3
CH3C.
O CH2CO + .
H .
H + .
CH3 + M CH4 + M
The symbol M represents a third body – any species in the reacting vapor. The
“dot” species like .
H are free radicals. A pseudo steady-state hypothesis (PSSH)
analysis (not shown here) of this 3-step mechanism consistent with the observed
rate data reveals that the slow step is the forward direction of the first step. This
suggests collapsing the first two steps into an effective single step:
CH3COCH3 CH2CO + .
CH3 + .
H
The presence of .
H and .
CH3 radicals can give rise to carbon deposition (coke)
through a complex set of rapid reactions not shown here. To acknowledge the
potential of this undesirable byproduct formation, three other elementary reactions
are added below. The C2H6 potentially can react further to form coke.
.
CH3 + .
CH3 + M C2H6 + M .
H + .
CH3 + M CH4 + M .
H + .
H + M H2 + M
Your Reactions and Kinetics
For this study, the following is your list of gaseous and vapor species with
abbreviations:
Let CH3COCH3 ≡ A, CH2CO ≡ B, C ≡ .
CH3, H ≡ .
H, E ≡ C2H6, G ≡ H2, N ≡ CH4
Here are your reactions and rates: NOTE: M = third body (any molecule)
2
A B + C + H r1 = k1CA (1)
H + C + M N + M r2 = k2CHCCCM (2)
C + C + M E + M 3 = 3
2 (3)
H + H + M G + M 4 = 4
2 (4)
k1 = 8.2E14 exp − 34222
T
sec-1 Source: Jeffreys (1964)
k2 =1.1E20 298
T
1.8
cm6/mole2-sec Source: NIST
k3 = 6.1E23 298
T
7.0
exp −1390
T
cm6/mole2-sec Source: NIST
= T
k E 298
4 2.2 15 cm6/mole2-sec Source: NIST
T = absolute temperature (K)
i need someone to solve it

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