For the chemical reaction A ⇌ B, the equilibrium constant Keq = 0.02 at 25°C. For the chemical reaction B ⇌ C, the equilibrium constant at 25°C is Keq = 1000
Determine the standard state Gibbs free energy (ΔG°’) for both these reactions. (Hint: note that the temperature is 25°C, which is 298.15 K)
Determine the equilibrium constant Keq and standard state Gibbs free energy (ΔG°’) for the chemical reaction A ⇌ C
The reaction pyruvate + ATP ⇌ ADP + PEP is catalyzed by the enzyme pyruvate kinase. ΔG°’ for this reaction is +31.4 kJ/mol.
Does this reaction move forward (from left to right) or backward under conditions of the standard state? What is meant by “standard state conditions” anyway?
Calculate the equilibrium constant (Keq) for this reaction at 25°C.
The concentrations of reactants and products of this reaction are measured in a particular cell at 37°C and found to be: pyruvate (24.9 mM); ATP (12.5 mM); ADP (0.14 mM); and PEP (0.01 mM). Calculate the Gibbs free energy for this reaction under these conditions.
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