At a certain temperature K = 1.1010 3 for the reaction: Fe 3+ (aq) + SCN – (aq) FeSCN 2+ (aq) 8.0010 -2 mol of Fe(NO 3 ) 3 is added to 1.02 L of…

At a certain temperature K = 1.10×103 for the reaction:

Fe3+(aq) + SCN-(aq) FeSCN2+(aq)

8.00×10-2 mol of Fe(NO3)3 is added to 1.02 L of 1.27×10-1 M KSCN.

Neglecting any volume change and assuming that all species remain in solution–:

Calculate the equilibrium concentration of Fe3+ (in mol/

i tried many times but didnot got the correct answer.. the answer I got is 0.002